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CHAPTER 44 - 4 - meson 2K=m c =135MeV,whichgivesK=67.5MeV...

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provide the rest energy of the p 0  meson: 2 K  =  m p0 c 2  = 135 MeV, which gives  K  =       67.5 MeV . 20. ( a ) For the decay  Ξ 0     Σ +  + p , the conservation laws are Charge:     0 = + 1 – 1; Energy (mass): 1314.9 MeV < 1189.4 MeV + 139.6 MeV; Thus this decay is       forbidden, energy is not conserved . ( b ) For the decay      Σ 0  + p  +  ν , the conservation laws are Charge:     – 1 = 0 – 1; Energy (mass): 1672.5 MeV > 1192.6 MeV + 139.6 MeV; Baryon number: + 1 = + 1 + 0 + 0; Lepton number: 0 ? 0 + 0 + 1. Thus this decay is       forbidden, lepton number is not conserved . ( c ) For the decay  Σ 0     Λ 0  +  γ γ , the conservation laws are Charge:     0 = 0 + 0 + 0; Energy (mass): 1192.6 MeV > 1115.7 MeV + 0 + 0; Baryon number: + 1 =  + 1 + 0 + 0; Lepton number: – 1 =  – 1 + 0 + 0.
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