CHAPTER 44 - 6 - e + e + B = b u For momentum conservation...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: e + e + B = b u For momentum conservation we have p p + 0 = p M , or ( p p c ) 2 = ( p M c ) 2 = E p 2 ( m p c 2 ) 2 = E M 2 ( Mc 2 ) 2 . When we combine this with the result from energy conservation, we get E p = [( Mc 2 ) 2 2( m p c 2 ) 2 ]/2 m p c 2 = {[( m p + m n + m p ) c 2 ] 2 2( m p c 2 ) 2 }/2 m p c 2 = [(938.3 MeV + 939.6 MeV + 139.6 MeV) 2 2(938.3 MeV) 2 ]/2(938.3 MeV) = 1230.7 MeV. For the kinetic energy we have K p = E p m p c 2 = 1230.7 MeV 938.3 MeV = 292.4 MeV . 29. For the decay , the electron will have maximum kinetic energy when the two neutrinos have the same momentum and move opposite to the direction of the electron. For a neutrino E = p c . For energy conservation we have m c 2 = E e + 2 E , or 2...
View Full Document

This note was uploaded on 09/13/2010 for the course PHYSICS 7 taught by Professor ? during the Spring '08 term at University of California, Berkeley.

Page1 / 2

CHAPTER 44 - 6 - e + e + B = b u For momentum conservation...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online