CHAPTER 44 - 8 - either or .Actuallyitisacombinationof u u...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
  u u   d d   u u   d d d _ d u _ d u u u _ p p š   0 š   0 u _ u _ d _ s d u d s u u u _ p K u _ u p K either   or  .  Actually it is a combination of  the two, but we will simplify the diagram by  assuming that one p 0  is   and the other is  .   We see that the exchanged particle is p + . We see that the exchanged particle is p. Note that high-energy  p    collisions  usually produce many particles.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
40. We see that the exchanged particle is p 0 . 41. The total energy of the proton is E  =  K  +  mc 2  = 25 GeV + 0.938 GeV =       26 GeV . We find the momentum from ( pc ) 2  =  E 2  – ( mc 2 ) 2  = (26 GeV) 2  – (0.938 GeV) 2 , which gives  pc  = 26 GeV. We find the wavelength from λ  =  h / p  =  hc / pc = (1.24 × 10 –12  MeV     m)/(26 GeV)(10 3  MeV/GeV) =       
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 2

CHAPTER 44 - 8 - either or .Actuallyitisacombinationof u u...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online