hw8_sol

# hw8_sol - Problem I. Homework 3 :9 f?” 51 gm 14%“ :: J....

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Unformatted text preview: Problem I. Homework 3 :9 f?” 51 gm 14%“ :: J. ?va13 d a}? 3' «=- L- 4‘41. H. j (1" eh“ ie 0"“ i 1' r '— 0 L (14+) “ﬂ ,7: *F — “HF/Ll '1....:*., J I K 1 l'h : 1* ' if; a ‘9‘ ,lﬁ "5 ._ (#3? I [I‘l— : 1.— F: Q! I; E Jot «Wyn- zﬂ'J- 1}:- H .L e : _’1_-"' ﬁg 2. Proceed in the similar manner ferfi X”: 1:- Y]. You will get the final answer as 2,3. l e— F/L ._ ‘ l :: " 'x 7" D ® ﬁM-— W 51035) 3*?“ .1 g V9 ﬁ(ﬂ-— 1 (TL _ 1—6 all; l "’ '2. Problem 2. a) The probability is obtained by integrating the joint pdi over the region indicated below. 3 8—2: P[X + Y 1: 3] = [ ze-ee-Zvdyda I oo y+lﬂ b) P[X — Y <_: 10] = A e-eaa2e-Evdy ﬂ 2 A (1.“ egiy+‘UJ)E-2ydy 2 = 1 — 35—“? y y = a“ — 10 P[X"' a; Y] H 1! DD m f / e'IZE'hdyda: ﬂ :2 CID / ewe—2‘: rim 1} 5% f” {Haﬁzﬁw a 1 1 m e-[t+%]3ﬂ(}} a! 2w ———-—d:1: V 4 a Fare) m i “I! ‘— ﬁﬂ E dz Let. .2 = \$ 2 1/211" i i EGG) mp— I3 all-— IE Pmbltm 3. _ @ Qt) {for V1: 9U. ’33.,Yinb‘] - E’Er~=**~.v¢-*~“31 7' QE\$:"II é-kﬁ‘r k.) : - .3... “‘ 41/; (193 mm m a with H 1 1 I; 3:. —2.1. d L P) 11 me. at}; £Dt PEX=MYE~31 : {Dew kaﬁ‘jj " E’Lm. Mics-l] __ -x "' 3-.— “111 @5133: &;, Lb} [Mb-1N : VP PK“) : P .__. mew/W I A! 1-" ______/_¢( -ﬁb 0.5”231 J _U 0-5 art at ﬁmﬁﬁﬁm= = E’EI‘F‘H NH» 0:] P'Lwrwwwmtan wwmwa H:ij = VCF=LI~55dLj (u-gﬁFEm-Q ai- PPEqu :- f’ at??? Lt—m Qtﬁfs) r? swam '5 g C3901] __________.——-—-—- Lrpﬁ at») + 93:01“ H #1:, {FF-h... 'l B ‘5“ J x../ 0,0128 #0. 0’22pr +03??? M 0:012:55 Jr'Dr‘i'SLlL/P PCKH [Yarn-1 >52: whim 0-6123 4:? z_._ \ H M 4-3.2- wKIM-x Oa?ﬁa.alzg XFK mm Limean Wm 6;; Etogmg’ {3/ / Problem 4. (3-) id )7: Ext.- % Kiwi-mm cal-L die, I M Xng, M 15me 5+ mbl~ Tk-ML (Xv, bi») +a+k¢z M «hex ﬂaw? mm \Xzz “Qwimm :3:w 5” _ W3 .u '5:___6__ +wl££ m r) ﬁzz-:- 32, LII?) 1 OlgbﬁhLPLUIg-L (Jib); (1:3);(135‘0! E?" / L1;.£);(.3;HL(5;92.(335); (my), ﬁgs), (536)} ._ . .523... PW (1"“2V‘Y)" 1% J “"0 6’ a; J ctr/W 1 Pmblem 5. X;: 4* 6% Mm [medzhﬁ 44% film: mam X1 * 1* 0-} bdm 4L4, fwt W mcmw* aria. (Eliza: X1=K‘)= ID(X1“K3 XII-Pg!) PCXfi'E-F) PDQ—— K!) = F Oﬂykl J [9(X2-ﬁki Eff—K!) '1 P<frP)K: klﬁgri,1_f_ J L-KtFI "I? kl“ 143 PM L(X*=Kr,¥;.5#:~) "1 j P; (JFaHFI-‘Kh in! MM KP. 2' 0" KL; 3&’ 1}...) :— ...
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## This note was uploaded on 09/14/2010 for the course ECE 302 taught by Professor Gelfand during the Spring '08 term at Purdue.

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hw8_sol - Problem I. Homework 3 :9 f?” 51 gm 14%“ :: J....

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