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Unformatted text preview: dziewa (jcd935) – Homework #10 – Holcombe – (52460) 1 This printout should have 14 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 10.0 points Determine the molar solubility of calcium chloride (CaCl 2 ) if K sp = 2 . 5 × 10 2 . 1. 0.005 M 2. 0.1 M 3. 10 M 4. 1 M 5. 4 M correct Explanation: The equation for K sp = x (2 x ) 2 = 4 x 3 x = parenleftbigg 1 4 K sp parenrightbigg 1 / 3 . Plugging in numbers gives you 3.97 M, or about 4 M. 002 10.0 points A saturated solution of MgF 2 (s) is found to have a Mg 2+ concentration of 2 . × 10 − 3 M. What is the value of K sp for MgF 2 ? 1. 3 . 2 × 10 − 8 correct 2. 1 . × 10 − 9 3. 4 . × 10 − 9 4. 8 . × 10 − 9 5. 4 . × 10 − 12 Explanation: [Mg 2+ ] = 2.0 × 10 − 3 M MgF 2 ⇀ ↽ Mg 2+ + 2 F − K sp = [Mg 2+ ] [F − ] 2 = ( x ) (2 x ) 2 = 4 x 3 = 4 ( 2 × 10 − 3 ) 3 = 3 . 2 × 10 − 8 003 10.0 points The molar solubility of PbSO 4 is 1 . 34 × 10 − 4 mol / L . What is the value for the K sp for PbSO 4 ? 1. 1 . 16 × 10 − 4 2. 8 . 8 × 10 − 11 3. 1 . 8 × 10 − 8 correct 4. 3 . × 10 − 99 5. 3 . 45 × 10 − 7 Explanation: PbSO 4 → Pb 2+ + SO 2 − 4 K sp = x 2 = (1 . 34 × 10 − 4 ) 2 = 1 . 8 × 10 − 8 . 004 10.0 points Arrange the compounds I) CuS K sp = 1 . 3 × 10 − 36 II) PbCl 2 K sp = 1 . 6 × 10 − 5 III) FeS K sp = 6 . 3 × 10 − 18 IV) Hg 2 Cl 2 K sp = 2...
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This note was uploaded on 09/14/2010 for the course C E 301 taught by Professor Staff during the Spring '08 term at University of Texas.
 Spring '08
 Staff

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