{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

418-Test1-Practice-NormalDistribution

# 418-Test1-Practice-NormalDistribution - Example An article...

This preview shows pages 1–5. Sign up to view the full content.

1 Example An article by Scott M. Berry titled “Drive for Show and Putt for Dough” ( Chance,1999, Vol. 12(4),pp. 50-54) discussed driving distances of PGA players. The mean distance for tee-shots on the 1999 men’s PGA tour is 272.2 yards with a standard deviation of 8.12 yards . Assume that the 1999 tee-shot distances are normally distributed. Example a. Find the percentage of tee-shots between 260 and 280 yards. b. Find the percentage of tee-shots greater than 300 yards. c. Find the 95 th percentile. 272.2 8.12 The mean distance for tee-shots on the 1999 men’s PGA tour is 272.2 yards with a standard deviation of 8.12 yards . Assume that the 1999 tee-shot distances are normally distributed.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
2 a. Find the percentage of tee-shots between 260 and 280 yards. 272.2 280 260 280.32 288.44 296.56 247.84 255.96 264.08 Graph of Procedure z 1 =(260-272.2)/8.12= = -12.2/8.12= = -1.50 z 2 =(280-272.2)/8.12= = 7.88/8.12= = 0.96 -1.5 0.96 0.43319 .76466 + 0.33147 Answer a. 76% of all tee-shots fall between 260 and 280 yards.
3 b. Find the percentage of tee-shots greater than 300 yards.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}