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418-Test1-Practice-NormalDistribution

418-Test1-Practice-NormalDistribution - Example An article...

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1 Example An article by Scott M. Berry titled “Drive for Show and Putt for Dough” ( Chance,1999, Vol. 12(4),pp. 50-54) discussed driving distances of PGA players. The mean distance for tee-shots on the 1999 men’s PGA tour is 272.2 yards with a standard deviation of 8.12 yards . Assume that the 1999 tee-shot distances are normally distributed. Example a. Find the percentage of tee-shots between 260 and 280 yards. b. Find the percentage of tee-shots greater than 300 yards. c. Find the 95 th percentile. 272.2 8.12 The mean distance for tee-shots on the 1999 men’s PGA tour is 272.2 yards with a standard deviation of 8.12 yards . Assume that the 1999 tee-shot distances are normally distributed.
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2 a. Find the percentage of tee-shots between 260 and 280 yards. 272.2 280 260 280.32 288.44 296.56 247.84 255.96 264.08 Graph of Procedure z 1 =(260-272.2)/8.12= = -12.2/8.12= = -1.50 z 2 =(280-272.2)/8.12= = 7.88/8.12= = 0.96 -1.5 0.96 0.43319 .76466 + 0.33147 Answer a. 76% of all tee-shots fall between 260 and 280 yards.
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3 b. Find the percentage of tee-shots greater than 300 yards.
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