tutorial6_sol

# tutorial6_sol - y ⊕ z 1 1 1 1 yz x 00 01 11 10 00 01 C=...

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ELEC151 Tutorial 6 • Design a combinational circuit with three inputs, x, y and z, and three outputs A, B, and C such that when the binary inputs is 0, 1, 2, or 3, the binary output is one greater than the input, and when the binary input is 4, 5, 6, 7, the binary output is one less than the input Example 1 A B C 0 0 1 0 1 0 0 1 1 1 0 0 0 1 1 1 0 0 1 0 1 1 1 0 x y z 0 0 0 0 0 1 0 1 0 0 1 1 1 0 0 1 1 1 0 1 1 1 0 1 Input Output Truth Table K-Maps are 1 1 1 1 yz x 00 01 11 10 00 01 A = xy+xz+yz 1 1 1 1 yz x 00 01 11 10 00 01 B = x

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Unformatted text preview: y ⊕ z 1 1 1 1 yz x 00 01 11 10 00 01 C= z’ • Hence the circuit is FA x y z c s x y z A B C A B C D A’ BC (A’D)’=A+D’ BC+A’ [(A’D)’A’]’=A+D F G Example 2 F=(A+D)(A’+BC)=A’D+ABC+BCD=A’D+ABC G=(A+D’)(A’+BC)=A’D’+ABC+BCD’=A’D’+ABC 1 1 1 1 1 1 CD AB 00 01 11 10 00 01 11 10 F=A’D+ABC+BCD=A’D+ABC G=A’D’+ABC+BCD’=A’D’+ABC F 1 1 1 1 1 1 CD AB 00 01 11 10 00 01 11 10 G Example 3...
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tutorial6_sol - y ⊕ z 1 1 1 1 yz x 00 01 11 10 00 01 C=...

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