problem44_57 - 44.57 From Pr(44.56 r = R R = So dR 1 dr r d...

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Unformatted text preview: 44.57: From Pr.(44.56): r = R R = So dR 1 dr r d 1 dr d = - 2 = since = 0. dt dt dt dt dt 1 dR 1 dr 1 dr dr 1 dR = = v= = r = H 0 r. So R dt R dt r dt dt R dt dv d r dR d dR =0= = Now d d R dt d dt dR = K where K is a constant. dt dR K d K = R = t since = 0. dt dt 1 dR K 1 H0 = = = . R dt Kt t 1 So the current value of the Hubble constant is where T is the present age of the T universe. r . ...
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This note was uploaded on 04/03/2008 for the course PHYS 2500 taught by Professor Kil during the Spring '08 term at Eastern Michigan University.

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