hwk3 - Tl'le 70—m-taJl tower is supponed by three cables...

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Unformatted text preview: Tl'le 70—m-taJl tower is supponed by three cables that exm forces FAB, and F , on it. The magnitude of each force is 2 kN. Express u -m exerted on the tower by the three cables in terms of scalar componertg.‘ r Rgs'UtrA'NT mam C’C_401_(0)4'o> — A. " V D'C’éOfO/féO) domnlflf a, gt} 35on NW. 192% z .2 £344) _ = "409703019 ,_ ' 'r g .r £5 4%“ 1’: H421,+OE ’7 (ca) Kfom’7gg40 11’058921 - Lee; +069é fix] — ’7' (via) Y ‘7?” = Z “Ms-we; —I z7’_/,09L<_ 23»! AD llo ' 9- i’fiije «1,74 4,51, - 1.27 = — 451 {m zgsfié: __ -0 3» 0.89-103 :— eoa. 1544.. "fir = «0.982: ~457j—O,213 ‘QJ 23 (14, 0, 14) ft Cables extend from A to B and fidm A to C. The cabie AC exerts a HBO-lb force F atA. ' . (a) What is the angle between the cables AB and AC? (b) Determine the vector component of F parallel to the cable AB. a men/m I h I BCOJO/IO) c 04, 0, I4) i ",“f’mflaludmwhmm. )M a; f; “DWMTZ mag?” “35‘ (015.6" per a '. ' ‘79»? é’J’*+Em~ ' A: A. “0“” F’Mbvfifl 60¢ 5-5?- ': 01852.3 + 0.25514, f? ' I g 0 F4 C(10)"? 0.83262.)+0';§g-€.‘> $5,641! I mow—pl M 91964 I a . eowdqu‘ a? FOE-=2 FED;- bflfiwnx +0.53% 0-“ 0k ...
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This note was uploaded on 09/16/2010 for the course CE 2450 taught by Professor ? during the Spring '08 term at LSU.

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hwk3 - Tl'le 70—m-taJl tower is supponed by three cables...

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