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hwk23

# hwk23 - 22 141 50 SHEETS 22—142 100 SHEETS 22-144 200...

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Unformatted text preview: 22 141 50 SHEETS 22—142 100 SHEETS 22-144 200 SHEETS 6%.. ﬂMFAD 1? 25D 1 ﬂué’é’Cto/tb‘ #35323 i Revolving the area of the triangle ABC about the x axis generates a conical volume. Use the second Pappus—Guldinus ”theorem to calculate the volume and compare your answer to the value given in Appendix C. {54E V=21roTA NH’EKE’ (15% 2A= ‘23, 2. 4w \l= 2W(E/3X“%)= 43—75sz _ wit? W lame )3 are ¢YLINDEE (A/a/mg aﬁcumk'tesié: Revolving the line A91; shown in Problem 7.86 about the .: ‘ .71 87 axis generates a conical surface. Use the ﬁrst Pappus—Guldinus A ’ _ _eorem to calculate the area of the conical surface. ' ‘ 7.; 3.A.=ZIEZJL NWL,” =%=Jh+ﬁzl 12/2 (Mlpranfopﬁs) R/ \$3. 7, E- 1: 6*; ‘5‘? 3A.¢zw[%(W + 32%)] r, maimﬁzlwmz 22-141 50 SHEETS ® - ANIF‘AD ‘ ?2 142 100 SHEETS 22-144 200 SHEETS @2457) 65‘ _ ﬂMEza/w ,WHL ' i 1% Determmeth V, 40M- e volume of the volume of revolutlon ‘ 03% V9 2775 IA WHERE I: {404 \$532; A— Hark/4:0) , 140+ /é 98 M24 —+ J = 159.95 M W A g 72/640)L: W75 A: 2575,27 W2 TM \/-: zW/sz 96myzs7; EVA/ma) 22-27394 5:3) V: 2478925 ”m3 2:; 0K 2.4aX/0W 7,97 ”hemmed L. M»: 344,-:— 274:5 1L) ' (40%;? W L): ﬁlial: WGF03= /2§éé/M; 0T" %+I4o = 5%:{0 a lama/m L15 93>me 2:140znwvx M, = 2T5 CW4 @M)£:0Mﬂ 2 79a \$74.0: 21F (am) 0 ZDIEOIYﬂM/Mz' 0K @ZOIXI [06 ...
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hwk23 - 22 141 50 SHEETS 22—142 100 SHEETS 22-144 200...

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