problem44_55 - 44.55: a) E ( m)c 2 (m )c 2 ( m 0 )c 2 (m )c...

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44.55: a) 2 2 2 Ξ 2 ) ( ) ( ) ( ) ( 0 c m c m c m c m E π - Λ - - - = = MeV. 65 MeV 139.6 MeV 1116 MeV 1321 = - - = E b) Using (nonrelativistic) conservation of momentum and energy: = = = Λ f P P 0 0 . 0 0 0 0 Λ Λ Λ Λ = - - - - - - v m m v v m v m π π π π Also E K K π = + - Λ 0 from part (a). So + = + = + - Λ Λ Λ Λ Λ Λ Λ - - - π π π π m m K v m m m K v m K 0 0 0 0 0 0 0 1 2 1 2 1 2 2 MeV. 8 . 57 MeV 2 . 7 65 MeV 2 . 7 MeV 6 .
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