hw3sol - The Hong Kong University of Science and Technology...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Page 1 of 2 The Hong Kong University of Science and Technology IS O M 111 - Business statistics, Fall Lecture Section (Prof Inchi HU) Assignment 3 (Problem Sheet 2: #10, #11, & #14; Q1 & Q2) Solutions 10. (a) (i) Three reasons for x to be a binomial random variables: 2 possible outcomes for each person: ‘having the disease’ & ‘not having the disease’ P(having the disease) is constant (= 0.005) The 1000 people are independent (ii) x ~ Bin(1000, 0.005) P( x 1) = 1 - P( x = 0) = 1 - q 1000 where q = 0.995 = 0.993346 (iii) P( x > 1 | x 1) = P( x 2) / P( x 1) = [ 1 - P ( x = 0) - P( x = 1)] / [1 - P( x = 0)] = [ 1 - q 1000 - 1000pq 999 ] / [1 - q 1000 ] = 0.959909 / 0.993346 = 0.966339 (iv) Let w be the number of people (excluding John) having the disease. W ~ Bin (999, p ) P( w > 0) = 1 - q 999 = 0.993313 (b) (i) Let N 1 be the number of tests performed for method 1. P
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 09/18/2010 for the course BBA ISOM111 taught by Professor Hu during the Fall '08 term at HKUST.

Page1 / 2

hw3sol - The Hong Kong University of Science and Technology...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online