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# 11-11 - A= 0.0034722 112 L = 2.5 ft p = 5.4 slugs/ft3 y=...

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Unformatted text preview: A= 0.0034722 112 L = 2.5 ft p = 5.4 slugs/ft3 y= 0.0173611 slugs/ft yL/6 = 0.0072338 slugs E = 4.18E+09 Ib/ft2 0.0144676 0.0072338 0 0 0 0 M“’= 0.0072338 0.0144878 M“): 0 0.0144676 0.0072338 0 0 0.0072338 0.0144676 00 O 0.0144676 0.0072338 0 M‘G’= 0.0072338 0.0289352 0.007234 0 0.0072338 0.014468 5.80E+06 -5.80E+06 o o 0 o K“’= -5.80E+06 5.80E+06 0 Km— 0 5.80E+06 -5.80E+06 0 o 0 0 -5.80E+06 5.80E+08 5.80E+06 -5800000 0 K‘°’= -5800000 11600000 -5800000 0 -5800000 5800000 Applying the boundary condition. M‘G’= 0.0289352 0.0072338 K‘G’= 11600000 ~5800000 0.0072338 0.0144676 ~5800000 5800000 M'1= 39.497145 49.74857 M"K= 572708808 -343625165 -19.74857 78.994291 887250330 572708808 (01 = 3.25E+O4 rad/s (02 = 9.31 E+03 rad/s ...
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