hw3examples - 18-100 HW3 Example Problems Fall 2006 Stephen...

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18-100 HW3 Example Problems Fall 2006 Stephen Tully [email protected] Example 1: Equivalent Resistance Determine the equivalent resistance between nodes A and B: Three paths lead to node B from node A. The first is the series combination of R 1 and R 2 . The second is simply R 4 by itself. The third is a series combination of R 3 , R 5 , and the parallel resistance R 6 || R 7 : Thus we can write an expression for R eq : R eq = (R 1 + R 2 ) || R 4 || (R 3 + R 5 + (R 6 || R 7 )) R eq = (10 + 20 ) || 60 || (20 + 30 + (30 || 45 )) R eq = (1/30 + 1/60) -1 || (50 + (1/30 + 1/45) -1 ) R eq = 20 || (50 + 18) R eq = (1/20 + 1/68) -1 = 15.45
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Example 2: Superposition Determine the voltages at A,B,C using superposition: 1) Assume only V x is on. This will short circuit the voltage source V y and open up the current source I z . Note: because the resistance R 2 is shorted out, it can be disregarded. V a1 = V x V b1 = V x R 3 / (R 1 + R 3 ) V c1 = V x R 3 / (R 1 + R 3 )
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2) Assume only V y is on. This will short circuit the voltage source V x and will open up the current source I z .
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This note was uploaded on 09/20/2010 for the course ECE 18100 taught by Professor Williams during the Fall '07 term at Carnegie Mellon.

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hw3examples - 18-100 HW3 Example Problems Fall 2006 Stephen...

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