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Unformatted text preview: . Imagine a measuring rod at rest in the moving frame S , where its proper length is L . An observer, stationary in S , calculates the length of the rod using the time interval between the passing of the two end of the rod at his origin O in S . From this he measures L = u t (19) in the stationary frame S . The observer in S , notices the passing of the two end of the rod at the origin to happen at L = L = u t (20) 3 Thus L L = L L = t t (21) But, from our result of time dilation, t t = 1 1( u/c ) 2 (22) therefore L = t t L = 1( u/c ) 2 L (23) therefore, the length of the rod is shorter when measured in a frame moving with respect to its stationary frame, with proper length L . 4...
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This note was uploaded on 09/20/2010 for the course AMATH 261 taught by Professor Rogermelko during the Spring '10 term at Waterloo.
 Spring '10
 RogerMelko

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