CS 70 Lecture 08

# CS 70 Lecture 08 - CS 70 Spring 2010 Discrete Mathematics...

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Discrete Mathematics and Probability Theory Spring 2010 Alistair Sinclair Note 8 Error Correcting Codes Erasure Errors We will consider two situations in which we wish to transmit information on an unreliable channel. The ﬁrst is exempliﬁed by the internet, where the information (say a ﬁle) is broken up into packets, and the unreliability is manifest in the fact that some of the packets are lost during transmission, as shown below: Suppose that the message consists of n packets and suppose that at most k packets are lost during transmis- sion. We will show how to encode the initial message consisting of n packets into a redundant encoding consisting of n + k packets such that the recipient can reconstruct the message from any n received packets. Note that in this setting the packets are labeled and thus the recipient knows exactly which packets were dropped during transmission. We can assume without loss of generality that the contents of each packet is a number modulo q , where q is a prime. For example, the contents of the packet might be a 32-bit string and can therefore be regarded as a number between 0 and 2 32 - 1; then we could choose q to be any prime larger than 2 32 . The properties of polynomials over GF ( q ) (i.e., with coefﬁcients and values reduced modulo q ) are perfectly suited to solve this problem and are the backbone of this error-correcting scheme. To see this, let us denote the message to be sent by m 1 , . . . , m n and make the following crucial observations: 1) There is a unique polynomial P ( x ) of degree n - 1 such that P ( i ) = m i for 1 i n (i.e., P ( x ) contains all of the information about the message, and evaluating P ( i ) gives the contents of the i - th packet). 2) The message to be sent is now m 1 = P ( 1 ) , . . . , m n = P ( n ) . We can generate additional packets by eval- uating P ( x ) at points n + j (remember, our transmitted message must be redundant, i.e., it must contain more packets than the original message to account for the lost packets). Thus the transmitted message is c 1 = P ( 1 ) , c 2 = P ( 2 ) , . . . , c n + k = P ( n + k ) . Since we are working modulo q , we must make sure that n + k q , but this condition does not impose a serious constraint since q is very large. 3) We can uniquely reconstruct P ( x ) from its values at any n distinct points, since it has degree n - 1. This means that P ( x ) can be reconstructed from any n of the transmitted packets. Evaluating this reconstructed polynomial P ( x ) at x = 1 , . . . , n yields the original message m 1 , . . . , m n . Example Suppose Alice wants to send Bob a message of n = 4 packets and she wants to guard against k = 2 lost packets. Then, assuming the packets can be coded up as integers between 0 and 6, Alice can work over GF ( 7 ) (since 7 n + k = 6). Suppose the message that Alice wants to send to Bob is m 1 = 3, m 2 = 1, m 3 = 5, and m 4 = 0. The unique polynomial of degree n - 1 = 3 described by these 4 points is

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## This note was uploaded on 09/21/2010 for the course CS 70 taught by Professor Papadimitrou during the Spring '08 term at Berkeley.

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CS 70 Lecture 08 - CS 70 Spring 2010 Discrete Mathematics...

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