su10q03

# su10q03 - f gure shows a MOSFET bias circuit Given V = 24V...

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ECE 3050 Analog Electronics Quiz 3 June 9, 2010 Professor Leach Last Name: First Name: Instructions. Print and sign your name in the spaces above. Place a box around answers when appropriate. Honor Code Statement: I have neither given nor received help on this quiz. Initials Equations: I D = K ( V GS V TO ) 2 , G m = ( r s + R ts ) 1 , r s = g 1 m , r id = r 0 (1 + g m R ts ) + R ts , r is = r s , r ig = . 1 of 2. The fi gure shows a MOSFET signal circuit that is called a phase splitter. It is given that R D = R S = 2 k , g m = 0 . 002 S , and r 0 = (open circuit). (a) Draw the Norton drain circuit and use it to solve for v o 1 as a function of v i . (b) Draw the Thévenin source circuit and use it to solve for v o 2 as a function of v i . (c) What might be the reason that the circuit is called a “phase splitter?” v o 1 = G m v i R D = R D r s + R S v i = 0 . 8 v i v o 2 = R S r s + R S v i = 0 . 8 v i The two outputs are 180 out of phase. 2 of 2. The fi

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Unformatted text preview: f gure shows a MOSFET bias circuit. Given: V + = 24V , R D = 11k Ω , R G = 100k Ω , R S = 1 . 2k Ω , K = 10 µ S / V 2 , and V TO = 1 . 8V . (a) Solve for V GG and R GG . V GG = V + − I D R D R GG = R G + R D (b) Write the loop equation for the gate-source loop and use it to solve for I D assuming the MOSFET is in its saturation state. V + − I D R D = r I D K + V TO + I D R S = ⇒ I D ( R D + R S ) + 1 √ K p I D + ¡ V TO − V + ¢ = 0 = ⇒ I D = 1mA (b) For the value of I D , check to verify that V DS > V GS − V TO for the MOSFET to be in the saturation state. V DS = ¡ V + − I D R D ¢ − ( I D R S ) = 11 . 8V V GS − V TO = r I D K = 10V 1 2...
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