CH22 HW1 - .2206 0.221 V/m Vm Vm 2 V/m 2 Question: MI3...

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1. 2/2 points All Submissions Notes Web Assign Ch22 HW1 S2010 (Homework) Kiyaniah Tilghman PY 208, section 003M, Spring 2010 Instructor: Keith Weninger Current Score : 13 / 13 Due : Monday, April 5, 2010 12:30 PM EDT About this Assignment Extension Requests Question Points 1 2 3 2 3 8 Total 13/13 (100.0%) Description Electric flux and Gauss's Law Instructions Reading: Sec. 22.1-22.3 The due date for this assignment is past. Your work can be viewed below, but no changes can be made. Question: MI3 22.X.001.alt01 If the electric field in the figure is 700 volts/meter, and the field is at an angle of 26 degrees to the outward-going normal, what is E ? 629.15 629 V/m
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2. 3/3 points All Submissions Notes 3. 8/8 points All Submissions Notes Question: MI3 22.X.010 The figure shows a disk-shaped region of radius 2 cm, on which there is a uniform electric field of magnitude 279 volts/meter at an angle of ! = 39 degrees to the plane of the disk. Calculate the electric flux on the disk, and include the correct units.
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Unformatted text preview: .2206 0.221 V/m Vm Vm 2 V/m 2 Question: MI3 22.X.011 The figure shows a box on whose surfaces the electric field is measured to be horizontal and to the right. On the left face (3 cm by 2 cm) the magnitude of the electric field E 1 is 270 volts/meter, and on the right face the magnitude of the electric field E 2 is 1160 volts/meter. On the other faces only the direction is known (horizontal). Calculate the electric flux on every face of the box, the total flux, and the total amount of charge that is inside the box. Flux through top Vm Flux through bottom Vm Flux through left-.162-0.162 Vm Flux through right .696 0.696 Vm Flux through front Vm Flux through back Vm Total Flux .534 0.534 Vm Total charge inside box (recall ! = 8.85 10-12 C 2 /Nm 2 ) 4.7259e-12 4.73e-12 C...
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This note was uploaded on 09/21/2010 for the course PY 005 taught by Professor Mattewk. during the Spring '10 term at N.C. State.

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CH22 HW1 - .2206 0.221 V/m Vm Vm 2 V/m 2 Question: MI3...

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