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HW8problem_pdf

# HW8problem_pdf - luu(nml299 HW08 markert(58710 This...

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luu (nml299) – HW08 – markert – (58710) 1 This print-out should have 19 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A coil is wrapped with 108 turns of wire on the perimeter of a square frame of sides 27 cm. Each turn has the same area, equal to that of the frame, and the total resistance of the coil is 4 . 14 Ω. A uniform magnetic field is turned on perpendicular to the plane of the coil. If the field changes linearly from 0 to 0 . 26 Wb / m 2 in a time of 0 . 962 s, find the mag- nitude of the induced emf in the coil while the field is changing. Answer in units of V. 002 10.0 points A solenoid with circular cross section pro- duces a steadily increasing magnetic flux through its cross section. There is an octago- nally shaped circuit surrounding the solenoid as shown. B B B B X Y i i Figure 1: The increasing magnetic flux gives rise to a counterclockwise induced emf E . The circuit consists of two identical light bulbs of equal resistance, R , connected in series, leading to a loop equation E − 2 i R = 0. Now connect the points C and D with a wire CAD (as in figure 2). Label the currents i 1 , i 2 , and i 3 as indicated. B B B B X Y D C A i 2 i 1 i 3 i 3 Figure 2: To what do the corresponding loop and node equations lead? 1. E − i 3 R = 0 : i 2 = i 3 4 , i 1 = 3 i 3 4 2. E − i 3 R = 0 : i 2 = i 3 2 , i 1 = i 3 2 3. E − 2 i 3 R = 0 : i 2 = i 3 3 , i 1 = 2 i 3 3 4. E − 2 i 3 R = 0 : i 2 = i 3 , i 1 = 0 5. E − 2 i 3 R = 0 : i 2 = i 3 4 , i 1 = 3 i 3 4 6. E − i 3 R = 0 : i 2 = 0 , i 1 = i 3 7. E − i 3 R = 0; i 2 = i 3 , i 1 = 0 8. E − 2 i 3 R = 0 : i 2 = i 3 2 , i 1 = i 3 2 9. E − 2 i 3 R = 0 : i 2 = 0 , i 1 = i 3 10. E − i 3 R = 0 : i 2 = i 3 3 , i 1 = 2 i 3 3 003 10.0 points A constant current is flowing through a solenoid, creating a magnetic field.

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luu (nml299) – HW08 – markert – (58710) 2 V I B conducting ring The force which the magnetic field exerts on a conducting ring positioned as shown is 1. There is no force, only a torque.
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HW8problem_pdf - luu(nml299 HW08 markert(58710 This...

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