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Unformatted text preview: EY = E ( E ( Y  X )), we get EY = E ( E ( Y  X )) = E ( X/ 2) = 1 / 4 . Also, we can st get the marginal density of Y by its conditional density and the marginal density of X, and then compute the expectation by denition. 4.6.7 Since Y denote the number of 6s that show up, we have ny rolls that are not 6s. 3/5 those should be odd(1, 3, and 5). Thus, the distribution of X conditional on Y is binomial (3 / 5) and the conditional expectation is E ( X  Y ) = 3 5 ( nY ) . Similarly, the distribution of Y given X is binomial (1 / 3) and the conditional expectation is E ( Y  X ) = 1 3 ( nX ) ....
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This note was uploaded on 09/22/2010 for the course MATH 413 at Cornell University (Engineering School).
 '08
 PROTSAK
 Math

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