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Unformatted text preview: mentioned above, and the routers are operating in store and forward mode. The message will get divided into 7 packets of size 24 bytes, or 192 bits each (for simplicity, we'll assume that the last one is padded out). The delays introduced by the three links are 3.43, 0.128 and 0.048 msecs each. The time it takes the message to reach the destination is really the time at which the seventh packet starts plus the delays introduced at the three links. The time at which 7th packet starts, assuming that 56kbps is the first link is 6x3.43. Add all the delays and you get 7x3.43+0.128+0.048 msec as the answer. Since the order of the links is not specified, assuming any one of them to be the starting link would be OK....
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This note was uploaded on 09/23/2010 for the course CHEM 402 taught by Professor Staff during the Spring '08 term at Ill. Chicago.
 Spring '08
 STAFF

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