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Unformatted text preview: Red LED Truth Table Truth Table Circuit #1 Circuit #2 G1 G2 G3 Y 0 0 1 0 0 1 1 0 1 1 0 1 1 1 1 0 1 1 0 1 1 1 1 1 1 1 1 B) C) SOP: POS: Circuit #1: F= AB+ABC Circuit #1: F=(AB)(C) Circuit #2: F=(AB+AC)+BC Circuit #2: F= (AB)+(AC)+(BC) Conclusion: This Lab was not very clear as how to derive our logical gates. Furthermore, I had trouble simplifying the Boolean equation we got from our second output (circuit 2). TA was helpful. After completing the Lab, it was straight forward as to how we are able to design a circuit for certain specifications. Overall this was a great learning lab, the instructions on the Lab should be more clear for the student to understand. G1 G2 G3 R 0 0 0 0 1 0 1 0 1 1 1 1 0 1 0 1 1 1 1 1 1 1 1 1...
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 Fall '08
 STAFF
 Logic, Boolean Algebra, TA, Logical connective, Propositional calculus

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