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Lesson_5_-_Example_Solutions_-2009

# Lesson_5_-_Example_Solutions_-2009 - Lesson 5 Example 5-1...

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Lesson 5 Example 5-1 Suppose that each of these reactions has 92% yield: (a) CH 4 + Cl 2 → CH 3 Cl + HCl (b) CH 3 Cl + Cl 2 → CH 2 Cl 2 + HCl Starting with 112 g of CH 4 in reaction (a) and an excess of Cl 2 , how many grams of CH 2 Cl 2 are formed in reaction (b)? Basis: 112 g CH 4 Data: M CH4 = 16 g/mol M CH2Cl2 = 85 g/mol ) yield l theoretica ( Cl CH mol 7 CH mol Cl CH mol 1 CH g 16 CH mol 1 CH g 112 3 4 3 4 4 4 = × × Cl CH mol 44 . 6 Cl CH mol 7 92 . 0 yield Actual 3 3 = × = 1

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Lesson 5 ) yield l theoretica ( Cl CH mol 44 . 6 Cl CH mol 1 Cl CH mol 1 Cl CH mol 44 . 6 2 2 3 2 2 3 = × 2 2 2 2 Cl CH mol 93 . 5 Cl CH mol 44 . 6 92 . 0 yield Actual = × = 2 2 2 2 2 2 2 2 Cl CH g 61 . 503 Cl CH mol Cl CH g 85 Cl CH mol 93 . 5 = × Single line calculation: 2
Lesson 5 2 2 2 2 2 2 2 2 2 2 3 2 2 3 3 4 3 4 4 4 Cl CH g 61 . 503 Cl CH mol Cl CH 6 85 l theoretica Cl CH mol actual Cl CH mol 92 . 0 Cl CH mol Cl CH mol 1 l theoretica Cl CH mol actual Cl CH mol 92 . 0 CH mol Cl CH mol 1 CH g 16 CH mol 1 CH g 112 = × × × × × × 3

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Lesson 5 Example 5-2 Silicon nitride (Si 3 N 4
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Lesson_5_-_Example_Solutions_-2009 - Lesson 5 Example 5-1...

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