Lesson_8_-_Example_Solutions_-2009

Lesson_8_-_Example_Solutions_-2009 - Lesson 8 Example 8-1...

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Lesson 8 Example 8-1 Calculate the root-mean-square and average speed in m/s at 25 o C for gaseous Ar atoms . Data: T = 25 o C = 298 K M Ar = 39.9 g/mol = 39.9x10 -3 kg/mol R = 8.3145 kg m 2 /s 2 mol K s / m 6 . 431 mol / kg 10 x 9 . 39 K 298 K mol s m kg 3145 . 8 3 M RT 3 u 3 2 2 rms = = = - M RT 8 u π = or more simply: ( 29 s / m 4 . 397 s / m 6 . 431 9208 . 0 u 225 . 1 128 . 1 u rms = = = Example 8-2 1
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Mixture of He and Ne at 300K, P T = 10 kPa was put in a spherical vessel. Gases effuse through a pinhole into surrounding vacuum. When P He = P Ne , Eff rate He = 2.25 Eff Rate Ne Rates of effusion of the 2 gases can be made equal by changing partial pressures (P T remains at 10 kPa). What is the P He in gas mixture to make the initial effusion rates equal? ____________________________________________________________________________________________ Basis: when P He = P Ne , Eff rate He = 2.25 Eff rate Ne 2 M RT 8 u π = Ne He Ne He Ne Ne He He u 25 . 2 u V N V N when A u V N 4 1
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This note was uploaded on 09/23/2010 for the course CHEM 103 taught by Professor Chem during the Fall '09 term at University of West Georgia.

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Lesson_8_-_Example_Solutions_-2009 - Lesson 8 Example 8-1...

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