Lesson_15_-_Example_Solutions-2009

Lesson_15_-_Example_Solutions-2009 - Lesson 15 Example 15-1...

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Lesson 15 Example 15-1 What weight of ethylene glycol (C 2 H 6 O 2 ) must be added to 1,000 g of water to lower the freezing point to –10 o C? Data: K f = 1.86 K/m Data: m 1 = 1000 g T f = -10 o C K f = 1.86 K.kg/mol M 2 = 62 g/mol T f = - K f m kg mol 38 . 5 mol / kg K 86 . 1 K 10 K T m f f = = - = O H kg O H C g 6 . 333 O H C mol O H C g 62 O H kg 1 O H C mol 38 . 5 m 2 2 6 2 2 6 2 2 6 2 2 2 6 2 2 = = 1
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Lesson 15 Example 15-2 The freezing point depression constant for HgCl 2 is 34.3 K/m. For a solution of 0.849 g of mercurous chloride (empirical formula HgCl) in 50g of HgCl 2 , the freezing point depression is 1.24 o C. What is the molecular weight of mercurous chloride? What is its molecular formula? Data: K f = 34.3 K.kg/mol m 2 = 0.849 g m 1 = 50 g T f = -1.24 o C M Hg = 200.6 g/mol M Cl = 35.5 g/mol ( 29 - = kg / g 1000 / m M / m K T 1 2 2 f f 2
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( 29 ( 29 ( 29 ( 29 ( 29 g 50 1 K 24 . 1 1 kg / g 1000 g 849 . 0 mol
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This note was uploaded on 09/23/2010 for the course CHEM 103 taught by Professor Chem during the Fall '09 term at University of West Georgia.

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Lesson_15_-_Example_Solutions-2009 - Lesson 15 Example 15-1...

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