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Lesson_17_-_Example_Solutions_-2009

Lesson_17_-_Example_Solutions_-2009 - Lesson 17 Example...

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Lesson 17 Example 17-1 The equilibrium constants for the following reactions have been measured at 823 K: CoO ( s ) + H 2 ( g ) = Co ( s ) + H 2 O ( g ) K p 1 = 67 CoO ( s ) + CO ( g ) = Co ( s ) + CO 2 ( g ) K p 2 = 490 From these data, calculate the equilibrium constant of the reaction at 823 K: CO 2 ( g ) + H 2 ( g ) = CO ( g ) + H 2 O ( g ) Solution: 2 H O 2 H 1 p P P K = CO 2 CO 2 p P P K = ( 29 ( 29 ( 29 ( 29 137 . 0 490 67 K K P P P P K 2 p 1 p 2 H 2 CO O 2 H CO 3 p = = = = 1

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Lesson 17 Example 17-2 A mixture that was initially at 0.005 M in H 2 ( g ) and 0.0125 M in I 2 ( g ) and contained no HI ( g ) was heated at 425.4 o C until equilibrium was reached. The equilibrium concentration of I 2 ( g ) was found by experiment to be 0.00772 M. What is the numerical value of K c for the following equilibrium? H 2 ( g ) + I 2 ( g ) = 2 HI ( g ) Solution: Basis: 1.0 L H 2 I 2 HI n i 0.005 0.0125 0 n 0.00478 0.00478 0.00956 n f 0.00022 0.00772 0.00956 [ ] [ ][ ] 2 2 2 c H I HI K = 2
Lesson 17 n I 2 = n i,I 2 n f,I 2 = (0.0125 – 0.00772) mol = 0.00478 mol I 2 ( 29 2 2 2 2 2 H H mol 00478 . 0 I mol 1 H mol 1 I mol 00478 . 0 n = = n f,H 2 = n i,H 2 n H 2 = (0.005 – 0.00478) mol = 0.00022 mol H 2 ( 29 HI mol 00956 . 0

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