Lesson_29_-_Example_Solutions_-2009

# Lesson_29_-_Example_Solutions_-2009 - 3 is 2 g O 3 g O 2 2...

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Lesson 29 Example 29-1 The decomposition reaction N 2 O 5 → NO 3 + NO 2 follows the mechanism: 2 N 2 O 5 ↔ N 2 O 5 * + N 2 O 5 N 2 O 5 * → NO 3 + NO 2 where N 2 O 5 * is a molecule at high energy level capable of decomposing into NO 3 and NO 2 . The experimentally-measured rate of reaction varies with N 2 O 5 concentration: At high [N 2 O 5 ] the reaction is 1 st order, but at low [N 2 O 5 ], the reaction is 2 nd order. Explain why the reaction order varies with [N 2 O 5 ]. ____________________________________________________________________________________________ 1

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Lesson 29 Example 29-2 The O 3 layer in earth’s upper atmosphere is important in shielding the earth from the harmful ultraviolet radiation. O 3 decomposes according to the equation The mechanism for the reaction is proposed to proceed through the following steps: Using the steady state approximation for the O radical, the rate for the decomposition of O
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Unformatted text preview: 3 is: ____________________________________________________________________________________________ 2 ) g ( O 3 ) g ( O 2 2 o k 3 → . s . d . r ) g ( O 2 ) g ( O ) g ( O ) g ( O ) g ( O ) g ( O 2 2 k 3 2 1 k 1 k 3 → + +-⇌ Lesson 29 3 ] O [ k ] O [ k ] O [ k ] O [ . a . s . s ] O ][ O [ k ] O ][ O [ k ] O [ k dt ] O [ d ] O [ k ] O [ k ] O [ k k 2 dt ] O [ d ] O [ k ] O [ k ] O [ k ] O [ k dt ] O [ d 2 1 ] O [ k ] O [ k ] O [ k ] O [ ] O ][ O [ k ] O ][ O [ k ] O [ k dt ] O [ d ] O ][ O [ k dt ] O [ d 2 1 3 2 2 1 3 1 3 2 2 1 3 1 3 2 1 3 2 2 3 2 1 3 3 2 2 1 3 1 3 2 3 3 2 2 1 3 1 3 2 2 1 3 1 3 2 3 + = +-=-+ =-+ =-+ =--= = =-------Apply steady state approximation for O radical...
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Lesson_29_-_Example_Solutions_-2009 - 3 is 2 g O 3 g O 2 2...

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