2010 PHYSICS 002C Lecture 03

2010 PHYSICS 002C Lecture 03 - PHYSICS 002C Lecture 03...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
PHYSICS 002C Lecture 03 April 02, 2010 Serway and Jewett Chapter 12 – Oscillatory Motion Reviev: Chap 12.1,2 Motion of a particle on a spring: Hooke’s law : kx F s Combine Hooke’s law and Newton’s 2 nd law to get , where x dt x d 2 2 2 / m k / 2 Solution: ) cos( t A x harmonic ” = sinusoidal motion, a consequence of Hooke’s law. simple ” = only one mode is excited. Chap 12.3 Energy of simple harmonic motion 2 2 1 mv K ; 2 2 1 kx U ; 2 2 1 kA U K E ; ) ( 2 2 2 1 2 2 1 x A k mv WHY is energy conserved? Because F=ma or the converse. Chap 12.4 Simple pendulum – Angular frequency for small amplitudes is , analogous to m k / . l g / Damped oscillations of a proton magnetic resonance signal. The restoring force is provided by gravity or the spring; resisting the motion is the length of the pendulum or the mass. The frequency to that tendency. New: Chap 12.6
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 2

2010 PHYSICS 002C Lecture 03 - PHYSICS 002C Lecture 03...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online