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PROBLEM 47 &amp; 48 May 24 2010

# PROBLEM 47 &amp; 48 May 24 2010 - element of atomic...

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Solving Problems 47 and 48 Phys 002C May 24 2010 Problem 47. (Like problem 29.4) The binding energy for a hydrogen state of quantum number n is R H / n 2 , where the wavelength of a photon with energy equal to R H is 91.1751 nm. What is the wavelength of the Balmer beta line for transitions from the n =4 to the n =2 level? (a) 656 nm; (b) 486 nm; (c) 434 nm; (d) 410 nm; (e) 397 nm What do you know? The energy levels are so the wavelengths are . Thus 2 / n R E H n H H n n n R hc n E hc 2 2 / / H H R 2 2 2 ( R E 16 3 2 4 ) 4 and nm H 3 . 486 3 18 . 91 16 3 16 2 4 Problem 48. (Like problem 29.37) Moseley showed that the characteristic x-rays from an
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Unformatted text preview: element of atomic number Z have a frequency approximately given by . For what value of Z would an element emit x-rays of wavelength 0.8333 nm? 2 15 ) 1 ( Hz 10 5 . 2 Z f (a) 2; (b) 5; (c) 13; (d) 19; (e) 37 What do you know? The frequency would be c/0.8333 nm = 3 10 8 ms-1 /0.8333 10-9 m=3.60 10 17 Hz. This means so Z=12+1=13. 144 10 5 . 2 / 10 6 . 3 Hz 10 5 . 2 / ) 1 ( 15 17 15 2 f Z...
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