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Unformatted text preview: (b) If there are four memory blocks per chip, the functional yield is (0.277) 4 = 0.6%. (c) If the memory block can be reconfigured to function with 25 or fewer defective amplifiers, the yield is now: 25 256 C k (0.995) 256 k (0.005) k k = We can use a Poisson approximation to this binomial distribution to ease evaluation, where = 0.005 256 = 1.28. Then the yield is given by 25 exp( ) k / k ! 1 k = 0...
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This note was uploaded on 09/24/2010 for the course MECHE 2.830J taught by Professor Davidhardt during the Spring '08 term at MIT.
- Spring '08