Test 1 - Version 314 Exam 1 McCord (53130) 1 This print-out...

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Unformatted text preview: Version 314 Exam 1 McCord (53130) 1 This print-out should have 30 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. McCord CH301tt This exam is only for McCords Tues/Thur CH301 class. c = 3 . 00 10 8 m/s h = 6 . 626 10- 34 J s m e = 9 . 11 10- 31 kg N A = 6 . 022 10 23 mol- 1 = R parenleftbigg 1 n 2 y- 1 n 2 x parenrightbigg where R = 3 . 29 10 15 s- 1 n ( x ) = parenleftbigg 2 L parenrightbigg 1 2 sin parenleftBig nx L parenrightBig E n = n 2 h 2 8 mL 2 n = 1 , 2 , 3 , 001 10.0 points Consider the electron filling diagram be- low: 3 p 3 s 2 p 2 s 1 s Which of the following does it violate? I) The aufbau principle II) The Pauli exclusion principle III) Hunds rule 1. I, II and III 2. III only 3. II and III 4. I and III correct 5. I and II 6. II only 7. I only Explanation: The half-filled 2 s subshell violates the auf- bau principle and the pairing of electrons in the 3 p subshell which still has one empty or- bital violates Hunds rule. 002 10.0 points A quantum mechanical particle in a box in its ground state is most likely to be found 1. is equally likely to be found at all positions except the very center of the box. 2. is equally likely to be found at all positions in the box. 3. at both edges of the box. 4. at the very edge of the box. 5. in the middle of the box. correct Explanation: The ground state is 1 which has maximum probability in the middle of the box. 003 10.0 points Which of the following would be expected to have the highest first ionization energy? 1. O 2. F 3. Li 4. C 5. Ne correct Explanation: Ionization energy generally decreases from Version 314 Exam 1 McCord (53130) 2 right to left across the Periodic Table. No- ble gases are most stable and have highest ionization energies. 004 10.0 points Write the ground-state electron configuration of a lead atom. 1. [Xe] 4 f 14 5 d 9 6 s 2 6 p 3 2. [Xe] 4 f 14 5 d 10 6 s 2 6 p 2 correct 3. [Xe] 4 f 14 5 d 10 6 s 1 6 p 3 4. [Xe] 4 f 14 5 d 10 6 p 4 5. [Xe] 4 f 14 5 d 5 6 s 1 6 p 6 7 s 2 Explanation: The Aufbau order of electron filling is 1 s , 2 s , 2 p , 3 s , 3 p , 4 s , 3 d , 4 p , 5 s , 4 d , 5 p , 6 s , 4 f , 5 d , 6 p , etc . s orbitals can hold 2 electrons, p orbitals 6 electrons, and d orbitals 10 electrons. Note some exceptions do occur in the electron con- figuration of atoms because of the stability of either a full or half-full outermost d-orbital, so you may need to account for this by shuffling an electron from the ( n- 1) s orbital. Finally use noble gas shorthand to get the answer: [Xe] 4 f 14 5 d 10 6 s 2 6 p 2 ....
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Test 1 - Version 314 Exam 1 McCord (53130) 1 This print-out...

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