M 408L HW04

# M 408L HW04 - kodeih(njk359 – HW04 – Henry –(54974 1...

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Unformatted text preview: kodeih (njk359) – HW04 – Henry – (54974) 1 This print-out should have 20 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 4) 10.0 points A Calculus student begins walking in a straight line from the RLM building towards the PCL Library. After t minutes his velocity v = v ( t ) is given (in multiples of 10 yards per minute) by the function whose graph is 2 4 6 8 10 − 2 2 4 6 − 2 t v How far is the student from the RLM build- ing at time t = 4? 1. dist = 95 yards 2. dist = 65 yards 3. dist = 75 yards correct 4. dist = 85 yards 5. dist = 115 yards Explanation: The student is walking towards the PCL Library whenever v ( t ) > 0 and towards RLM whenever v ( t ) < 0. The distance he has walked is given by 10 times the area between the graph of v and the t axis since 1 unit is equivalent to 10 yards. Now at t = 4 this area is 7 . 5 units, so the student has walked a distance of 75 yards. 002 (part 2 of 4) 10.0 points How far is the student from the RLM build- ing at time t = 7? 1. dist = 210 yards correct 2. dist = 230 yards 3. dist = 250 yards 4. dist = 220 yards 5. dist = 200 yards Explanation: The distance the student has walked is given by the area between the graph of v and the t axis. Now at t = 7 this area is 21 units, so the student has walked a distance of 210 yards. 003 (part 3 of 4) 10.0 points What is the total distance walked by the student from time t = 0 to t = 10? 1. dist = 240 yards 2. dist = 290 yards 3. dist = 260 yards correct 4. dist = 250 yards 5. dist = 270 yards Explanation: The distance the student has walked is given by the area between the graph of v and the t axis. Now at t = 10 this area is 26 units (area is always positive remember), so the student has walked a distance of 260 yards. 004 (part 4 of 4) 10.0 points How far is the student from the RLM build- ing when he turns back? 1. dist = 240 yards correct 2. dist = 210 yards kodeih (njk359) – HW04 – Henry – (54974) 2 3. dist = 230 yards 4. dist = 260 yards 5. dist = 280 yards Explanation: The student will turn back when his veloc- ity changes from postive to negative, i.e. , at t = 8. At this time he is 240 yards from the RLM building. keywords: distance, time, graph, velocity, area 005 10.0 points Determine the indefinite integral I = integraldisplay 4 − 6 x √ x dx . 1. I = 4 x 1 / 2 + 2 x 3 / 2 + C 2. I = 4 x 1 / 2 − 4 x 3 / 2 + C 3. I = 8 x 1 / 2 − 2 x 3 / 2 + C 4. I = 8 x 1 / 2 − 4 x 3 / 2 + C correct 5. I = 4 x 1 / 2 + 4 x 3 / 2 + C 6. I = 8 x 1 / 2 + 4 x 3 / 2 + C Explanation: After division we see that 4 − 6 x √ x = 4 √ x − 6 √ x = 4 x − 1 / 2 − 6 x 1 / 2 ....
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## This note was uploaded on 09/25/2010 for the course M 54980 taught by Professor Henry during the Fall '10 term at University of Texas.

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M 408L HW04 - kodeih(njk359 – HW04 – Henry –(54974 1...

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