This preview shows pages 1–11. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: alpha and Ag are independent. Hence, a ball sliding and rotating performs an unconstrained plane motion. Ball rolls without slipping then Acx=0 and Ag=alpha*r. Now there is a relationship between Ag and alpha making them dependent. This motion is constrained. Ball slips in this problems so use case A. • In constrained motion, a definite relation exists between the components of acceleration abar of the mass center and alpha • Pure rotation is tangential and normal equations, abar=alpha*rbar +w^2*rbar • If we take moment about pin O, it is Mo=Io*alpha • We can now take moment about O in constrained case as well Summary: Ag doesn’t depend on alpha so unconstrained motion...
View Full
Document
 Spring '10
 chase
 Dynamics, Strain

Click to edit the document details