{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

55010Solution3

# 55010Solution3 - STAT 550 HW#3 Solution 1.5-1 sample space...

This preview shows pages 1–3. Sign up to view the full content.

STAT 550 HW #3 Solution 1.5-1 {( , ), , 1 6} {(3,4),(4,3)} { 7} {(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)} 2 6 1 2 ( ) , ( ) , ( ) 36 36 6 36 ( ) 2 / 36 1 ( | ) ( ) 1/ 6 3 sample space S i j i j A B the sum of face is P A P B P A B P A B P A B P B = = = = = = = = = = = = K I I 1.5-4 (a) 5 5 4 1 1 1 5 5 4 3 ⎞⎛ ⎞⎛ ⎟⎜ ⎟⎜ ⎠⎝ ⎠⎝ + + (b) Let A, B, C be events that there is a person selected in Democrats, Republicans and Independents respectively: 1 1 1 5 5 4 1 1 1 14 13 12 ( ) ( ) ( | ) ( | ) P A B C P A P B A P C A B C C C C C C = = 1.5-5 (a) 0.15 1 ( 4 | ) 0.6 4 P more than hours student is in a tech area = = (b) 0.15 3 ( | 4 ) 0.15 0.05 4 P student is in a tech area more than hours = = + (c) 0.20 0.15 7 ( | 4 ) 0.25 0.55 16 P student is in a nontech area less than or equal to hours + = = + 1.5-6 Let E be an event that red marble is selected in BOX I; A be an event that the marble is red in BOX II. Then 2 2 4 ( ) , ( ) , ( | ) , ( | ) 4 4 6 C C P E P E P A E P A E = = = 3 6 = By the total probability, we have 2 4 2 3 7 ( ) ( ) ( | ) ( ) ( | ) 4 6 4 6 12 C C P A P E P A E P E P A E = + = × + × = 1.5-8 Let A be the event that a student will graduate, E be the event that a student will study 1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document