soln3 - EE212 - Assignment 3 Solutions Problem #1 Thevenin...

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EE212 - Assignment 3 Solutions Problem #1 Thevenin equivalent at the terminals A-B of the following circuit. Calculation of Thevenin Voltage, E Th : Using Mesh Analysis, The equations are j5 Ι 2 = j100 -5 Ι 1 + (10-j10) Ι 2 + j5 Ι 3 = -j50 j5 Ι 2 + 10 Ι 3 = 0 Using Cramer’s rule A j j j j j j j j j j j j j j j j j j j j j I - = - = - - = - - - = 10 50 500 0 10 5 0 5 5 0 5 100 5 5 10 5 0 5 10 10 5 0 5 0 0 5 0 50 10 10 5 100 5 0 2 3 E TH = V AB = (-j10) * (j5) = 50 /0 0 Volts 50 90 0 -j5 -j5 10 j5 10 50 - 90 0 A B j5 + - + - + - + - I 1 I 2 I 3 50 90 0 -j5 -j5 10 j5 10 50 - 90 0 A B j5
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Thevenin Impedance, Z Th across terminals A-B Z 1 || Z 4 , the equivalent value Z a : Z a = (j5) * (-j5) / (j5 – j5) = Infinite impedance represents an open circuit. b : Z b = 10 – j5 Z Th = Z b || Z 6 = (10 - j5) * (j5) / (10-j5+j5) = (j50 + 25) / 10 = (2.5 +j5) Thevenin Equivalent Circuit Norton Equivalent Circuit Ι N = 50
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This note was uploaded on 09/25/2010 for the course EE 212 taught by Professor Gander during the Spring '10 term at University of Saskatchewan- Management Area.

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soln3 - EE212 - Assignment 3 Solutions Problem #1 Thevenin...

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