Unformatted text preview: A 2 . The frequency of A 1 is 978/1708 = 0.57, and the frequency of A 2 is 730/1708 = 0.43. 3. The given data are q 2 = 0.04 and p 2 + 2 pq = 0.96. Assuming Hardy–Weinberg equilibrium, if q 2 = 0.04, q = 0.2, and p = 0.8. The frequency of B/B is p 2 = 0.64, and the frequency of B/b is 2 pq = 0.32....
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This note was uploaded on 09/25/2010 for the course BIOL 3301 taught by Professor Gunaratne during the Fall '05 term at University of Houston.
 Fall '05
 Gunaratne
 Genetics, Population Genetics, Mutation

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