26 OMIS 1000 C - Assignment 2 - Solution

26 OMIS 1000 C - Assignment 2 - Solution - OMIS 1000 C...

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OMIS 1000 C I NTRODUCTION TO S TATISTICS F ALL 2007 A LEXANDER S HOUMAROV A SSIGNMENT 2 S OLUTION Total of 29 marks Question 1 (total of 19 marks) Given: P(uses the Web) = P(W) = 0.21 P(does not use the Web) = P(W’) = 1-0.21 = 0.79 P(female given that uses the Web) = P(F|W) = 0.58 P(male given that uses the Web) = P(M|W) = 0.42 P(male given that does not use the Web) = P(M|W’) = 0.58 P(female given that does not use the Web) = P(F|W’) = 0.42 Part a. (6 marks) If the binomial formula is not shown for each calculation, the grade for this part is 0. Example for X=2: 2174 . 0 ) 4930 . 0 )( 0441 . 0 ( ) 6 )( 2 ( 120 ) 79 . 0 ( ) 21 . 0 ( )! 2 5 ( )! 2 ( ! 5 ) 2 X ( P 3 2 = = - = = The parameters for a binomial distribution are simply the values of p, n and x. X P 0 0.3077 1 0.4090 2 0.2174 3 0.0578 4 0.007 5 0.0004
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Part b. (2 marks each, total of 8) Tree, formula and table approaches are all fine. This is the contingency table: Joint (inside table) M F Marginal W 0.0882 0.1218 0.21 W’
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This note was uploaded on 09/25/2010 for the course OMIS OMIS 1000 taught by Professor Alexandershoumarov during the Fall '09 term at York University.

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26 OMIS 1000 C - Assignment 2 - Solution - OMIS 1000 C...

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