solution10_pdf

# solution10_pdf - valdez(vv689 Homework#10 Holcombe(52460...

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valdez (vv689) – Homework #10 – Holcombe – (52460) 1 This print-out should have 14 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 10.0 points Determine the molar solubility oF calcium chloride (CaCl 2 ) iF K sp = 2 . 5 × 10 2 . 1. 1 M 2. 0.005 M 3. 10 M 4. 0.1 M 5. 4 M correct Explanation: The equation For K sp = x (2 x ) 2 = 4 x 3 x = p 1 4 K sp P 1 / 3 . Plugging in numbers gives you 3.97 M, or about 4 M. 002 10.0 points A saturated solution oF Mg± 2 (s) is Found to have a Mg 2+ concentration oF 2 . 0 × 10 3 M. What is the value oF K sp For Mg± 2 ? 1. 4 . 0 × 10 12 2. 8 . 0 × 10 9 3. 3 . 2 × 10 8 correct 4. 1 . 0 × 10 9 5. 4 . 0 × 10 9 Explanation: [Mg 2+ ] = 2.0 × 10 3 M Mg± 2 Mg 2+ + 2 ± K sp = [Mg 2+ ] [± ] 2 = ( x ) (2 x ) 2 = 4 x 3 = 4 ( 2 × 10 3 ) 3 = 3 . 2 × 10 8 003 10.0 points The molar solubility oF PbSO 4 is 1 . 34 × 10 4 mol / L . What is the value For the K sp For PbSO 4 ? 1. 8 . 8 × 10 11 2. 3 . 45 × 10 7 3. 1 . 16 × 10 4 4. 1 . 8 × 10 8 correct 5. 3 . 0 × 10 99 Explanation: PbSO 4 Pb 2+ + SO 2 4 K sp = x 2 = (1 . 34 × 10 4 ) 2 = 1 . 8 × 10 8 . 004 10.0 points Arrange the compounds I) CuS K sp = 1 . 3 × 10 36 II) PbCl 2 K sp = 1 . 6 × 10 5 III) ±eS K sp = 6 . 3 × 10 18 IV) Hg 2 Cl 2 K sp = 2 . 6 × 10 18 V) Cu 2 S K sp = 2 . 0 × 10 47 in increasing order oF molar solubility.

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solution10_pdf - valdez(vv689 Homework#10 Holcombe(52460...

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