hw2_sol

hw2_sol - Stat 503 Homework#2(80pts 1(10pts The mean and SD...

This preview shows pages 1–2. Sign up to view the full content.

Stat 503 Homework #2 (80pts) 1. (10pts) The mean and SD of a set of 47 body temperature measurements were as follows: y = 36.497 °C s = 0.172 °C If the measurements were converted to °F, and the conversion from Celsius to Fahrenheit is y’ = 1.8 y + 32. (a) (5pts) What would be the new mean and SD? The conversion from Celsius to Fahrenheit is F = y’ = 1.8 y + 32. The new mean would be y’ = 1.8 y + 32 = 1.8(36.497) + 32 = 65.6946 + 32 = 97.6946 97.7. The new SD would be s’ = 1.8 s = 1.8(0.172) = 0.3096 0.31 (b) (5pts) What would be the new coefficient of variation? The new coefficient of variation would be s’/ y’ = 0.3096/97.6946 = 0.003169 0.0032. 2. (10pts) A researcher measured the average daily gains (in kg/day) of 20 beef cattle; typical values were 1.39, 1.57,1.44,… The mean of the data was 1.461 and the standard deviation was .178. (a) (5 pts) Express the mean and std in lb/day. ( Hint: 1 kg=2.2 lb) ' (2.2) yy , hence, the new mean = (2.2)1.461=3.214 lb/day The SD=(2.2)0.178=0.392 (b) (5 pts) What is the mean and std after we standardize the data? Mean=0 and std=1 3.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 09/26/2010 for the course STAT 503 taught by Professor Staff during the Fall '08 term at Purdue.

Page1 / 3

hw2_sol - Stat 503 Homework#2(80pts 1(10pts The mean and SD...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online