hw2_sol - Stat 503 Homework #2 (80pts) 1. (10pts) The mean...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Stat 503 Homework #2 (80pts) 1. (10pts) The mean and SD of a set of 47 body temperature measurements were as follows: y = 36.497 °C s = 0.172 °C If the measurements were converted to °F, and the conversion from Celsius to Fahrenheit is y’ = 1.8 y + 32. (a) (5pts) What would be the new mean and SD? The conversion from Celsius to Fahrenheit is F = y’ = 1.8 y + 32. The new mean would be y’ = 1.8 y + 32 = 1.8(36.497) + 32 = 65.6946 + 32 = 97.6946 97.7. The new SD would be s’ = 1.8 s = 1.8(0.172) = 0.3096 0.31 (b) (5pts) What would be the new coefficient of variation? The new coefficient of variation would be s’/ y’ = 0.3096/97.6946 = 0.003169 0.0032. 2. (10pts) A researcher measured the average daily gains (in kg/day) of 20 beef cattle; typical values were 1.39, 1.57,1.44,… The mean of the data was 1.461 and the standard deviation was .178. (a) (5 pts) Express the mean and std in lb/day. ( Hint: 1 kg=2.2 lb) ' (2.2) yy , hence, the new mean = (2.2)1.461=3.214 lb/day The SD=(2.2)0.178=0.392 (b) (5 pts) What is the mean and std after we standardize the data? Mean=0 and std=1 3.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 3

hw2_sol - Stat 503 Homework #2 (80pts) 1. (10pts) The mean...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online