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Unformatted text preview: Angular momentum Algebraic theory Eigenfunctions of angular momentum: zero momentum We consider several examples of the eigenfunctions. We begin with a wave function, which depends only on the distance from a center of the coordinate system. 0,0 ( ) ( ) R r = r Apply operator of the orbital momentum to this function ( ) i R r r h ( ) ( ) r r dR dR R r i R r i dr dr =  =  = e r r e h h Thus, all components of the angular momentum in this state have definite value of zero. Probability distribution in this case is fully angle independent (isotropic) and can be presented as a sphere Eigenfunctions of angular momentum: l=1 Consider the following functions ( 29 ( 29 1,0 1,1 1, 1 ( ); ( ); ( ) zR r x iy R r x iy R r  = = + = And check how components of the operator of the angular momentum acts on them ( 29 ( 29 1,0 1,1 1, 1 ( ) ( ) ( ) ( ) ( ) ( ) 1 z z z dR r dR r L i x y zR r i z x y y x dr y dr x dR r r dR y x i z x y i z x y m dr y x dr r r L i x y xR r iyR r i yR r xR r x iy R r m y x L i x y y x  =  =  =  =  = = =  + = + = + = =  h h h h h h h h h ( 29 ( 29 ( ) ( ) ( ) ( ) ( ) 1 xR r iyR r i yR r xR r x iy R r m  = =  =  h h h Probability distributions are in this case ( 29 2 2 2 2 2 2 2 2 2 2 2 1,0 1, 1 cos ; sin P z R r R P x y R r R = = = + = Eigenfunctions of angular momentum: l=1 Again consider the following functions 1,0 ( ) zR r = 2 2 1,0 x yz y L i y z zR i yR R z R i yR z y r r =  =  + =  h h h As expected this function is not an eigenfunction of the xcomponent of momentum At the same it is the eigefunction of the square of this component ( 29 2 2 2 2 2 2 1,0 x z y L y z yR y zR z zR zR z y r r =  =  = h h h Doing the same with ycomponents we have ( 29 2 2 1,0 2 2 2 2 2 2 1,0 y y xz x L i x z zR i xR R z R i xR z x r r z x L x z xR x R zR z zR z x r r =  + =  + = = + = + + = h h h h h h Finally, considering the square of the momentum ( 29 ( 29 ( 29 2 2 2 2 2 2 1,0 2 x y z L L L zR zR zR + + = + + = h h h Which corresponds to l=1 Momentum operator in spherical coordinates Spherical coordinates are related to Cartesian coordinates by 2 2 2 2 2 2 sin cos ; sin sin ; cos ;cos ; tan x r y r z r z y r x y z x x y z = = = = + + = = + + Using these relations we can express components and the square of the angular momentum operator in the spherical coordinates...
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This note was uploaded on 09/27/2010 for the course PHYSICS 365 taught by Professor Deych during the Spring '10 term at SUNY Stony Brook.
 Spring '10
 deych
 Angular Momentum, Momentum

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