# hw 16 - rhodes(ajr2283 – HW16 – Gilbert –(56380 1...

This preview shows pages 1–3. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: rhodes (ajr2283) – HW16 – Gilbert – (56380) 1 This print-out should have 16 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points By changing to polar coordinates evaluate the integral I = integraldisplay integraldisplay R radicalbig x 2 + y 2 dxdy when R is the region braceleftBig ( x, y ) : 9 ≤ x 2 + y 2 ≤ 25 , y ≥ bracerightBig in the xy-plane. 1. I = 89 3 π 2. I = 95 3 π 3. I = 98 3 π 4. I = 92 3 π 5. I = 86 3 π 002 10.0 points By changing to polar coordinates evaluate the integral I = integraldisplay integraldisplay R 2 e- x 2- y 2 dxdy when R is the region in the xy-plane bounded by the graph of x = radicalbig 9- y 2 and the y-axis. 1. I = 2 π (1- e- 9 ) 2. I = 1 2 π (1- e- 9 ) 3. I = π (1- e- 3 ) 4. I = π (1- e- 9 ) 5. I = 2 π (1- e- 3 ) 6. I = 1 2 π (1- e- 3 ) 003 10.0 points The solid shown in lies inside the sphere x 2 + y 2 + z 2 = 25 and outside the cylinder x 2 + y 2 = 16 . Find the volume of the part of this solid lying above the xy-plane. 1. volume = 27 2. volume = 9 π 3. volume = 9 4. volume = 27 π 5. volume = 18 π 6. volume = 18 004 10.0 points The plane z = 5 rhodes (ajr2283) – HW16 – Gilbert – (56380) 2 and the paraboloid z = 7- 2 x 2- 2 y 2 enclose a solid as shown in z y x Use polar coordinates to determine the vol- ume of this solid.ume of this solid....
View Full Document

## This note was uploaded on 09/27/2010 for the course M 408 D taught by Professor Textbookanswers during the Spring '07 term at University of Texas.

### Page1 / 6

hw 16 - rhodes(ajr2283 – HW16 – Gilbert –(56380 1...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online