hw 16 - rhodes(ajr2283 – HW16 – Gilbert –(56380 1...

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Unformatted text preview: rhodes (ajr2283) – HW16 – Gilbert – (56380) 1 This print-out should have 16 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points By changing to polar coordinates evaluate the integral I = integraldisplay integraldisplay R radicalbig x 2 + y 2 dxdy when R is the region braceleftBig ( x, y ) : 9 ≤ x 2 + y 2 ≤ 25 , y ≥ bracerightBig in the xy-plane. 1. I = 89 3 π 2. I = 95 3 π 3. I = 98 3 π 4. I = 92 3 π 5. I = 86 3 π 002 10.0 points By changing to polar coordinates evaluate the integral I = integraldisplay integraldisplay R 2 e- x 2- y 2 dxdy when R is the region in the xy-plane bounded by the graph of x = radicalbig 9- y 2 and the y-axis. 1. I = 2 π (1- e- 9 ) 2. I = 1 2 π (1- e- 9 ) 3. I = π (1- e- 3 ) 4. I = π (1- e- 9 ) 5. I = 2 π (1- e- 3 ) 6. I = 1 2 π (1- e- 3 ) 003 10.0 points The solid shown in lies inside the sphere x 2 + y 2 + z 2 = 25 and outside the cylinder x 2 + y 2 = 16 . Find the volume of the part of this solid lying above the xy-plane. 1. volume = 27 2. volume = 9 π 3. volume = 9 4. volume = 27 π 5. volume = 18 π 6. volume = 18 004 10.0 points The plane z = 5 rhodes (ajr2283) – HW16 – Gilbert – (56380) 2 and the paraboloid z = 7- 2 x 2- 2 y 2 enclose a solid as shown in z y x Use polar coordinates to determine the vol- ume of this solid.ume of this solid....
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This note was uploaded on 09/27/2010 for the course M 408 D taught by Professor Textbookanswers during the Spring '07 term at University of Texas.

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hw 16 - rhodes(ajr2283 – HW16 – Gilbert –(56380 1...

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