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Unformatted text preview: Version 019 – Midterm 01 – Yao – (57045) 1 This printout should have 11 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 10.0 points Light strikes the surface of a prism, n = 1 . 61, as shown in the figure. 45 ◦ If the prism is surrounded by a fluid, what is the maximum index of refraction of the fluid that will still cause total internal reflection within the prism? 1. 1.13844 2. 1.26572 3. 1.28693 4. 1.25158 5. 1.18087 6. 1.11016 7. 1.16673 8. 1.31522 9. 1.06773 10. 1.33643 Correct answer: 1 . 13844. Explanation: Basic Concept: sin θ c = n r n i Given: n i = 1 . 61 θ c = 45 ◦ Solution: sin θ c = n r n i n r = n i (sin θ c ) = 1 . 61(sin 45 ◦ ) = 1 . 13844 002 10.0 points Hint: Use a small angle approximation; e.g. , sin θ ≈ tan θ ≈ θ and cos θ ≈ 1 . Consider the setup of doubleslit experiment in the schematic drawing below. Note: As can be seen in the figure below, one of the doubleslit interference maxima is located at the first singleslit diffraction minimum. a d y L S 1 S 2 θ viewingscreen Determine the ratio d a ; i.e. , the slit separa tion d compared to the slit width a . 1. d a = 9 2 2. d a = 7 2 3. d a = 5 4. d a = 3 2 5. d a = 3 correct 6. d a = 1 7. d a = 11 2 8. d a = 2 Version 019 – Midterm 01 – Yao – (57045) 2 9. d a = 4 10. d a = 5 2 Explanation: At y there is a minimum for singleslit diffraction and a maxima for doubleslit in terference, as noted in the question . The first minimum for singleslit diffraction occurs when sin θ = λ a , (1) and the maxima for doubleslit interference occur when sin θ = ( m ) λ d . (2) The first diffraction minimum for singleslit diffraction and the third doubleslit interfer ence maximum ( m = 3) occur at the same position y , as seen in the figure below....
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This note was uploaded on 09/27/2010 for the course PHY 58650 taught by Professor Yao during the Fall '10 term at University of Texas at Austin.
 Fall '10
 YAO

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