Eval- - ME 3322 Thermodynamics Fall 2009 Evaluation Problems Name Date Instructions This is a closed-book closed-notes exam Any necessary equations

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ME 3322 — Thermodynamics Name: Fall 2009 — Evaluation Problems Date: Instructions This is a closed-book, closed-notes exam. Any necessary equations you may need are listed in the problem itself or on the formula sheet. You will need a calculator. 1. Write the solution for each problem separately. 2. Use only the front side of each sheet of paper. 3. Be organized, clear, and neat. 4. Don’t substitute in values until you need to. 5. Use proper units in all calculations. 6. Be consistent with your sign convention for heat and work from the very beginning. Honor Pledge On my honor, I pledge that I have neither given nor received inappropriate aid in the preparation of this assignment. Signature No. Do not turn in your work. Yes. Turn in your work for grading. For each problem you solved, did you get the correct answer?
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ME 3322 Thermodynamics – Formula Sheet Page 1 Control Volume Balance Equations (uniform flow) Sign convention: , , and W are positive going into the control volume m ± Q ± ± c V and negative going out . Mass, m ,/ dm mmA V v dt == ±± Energy, E () 2 1 2 , dE QW mh V g z EU K E P E dt =++ + + =+ + ± ± ± Entropy, S ,0 s dS Q ms dt T Σ Σ ± ± Expansion Work Equations Rate form: d Wp dt =− ± V Process form: 2 12 1 V d Heat Transfer Rate Equations Conduction dT Qk A dx ± positive in the positive x -direction Convection 0 s Qh A TT ± positive from the surface at T s to the surroundings at T 0 , T s > T 0 Radiation 44 0 s QA T T εσ ± positive from the surface at T s to the surroundings at T 0 , T s > T 0 Polytropic Process Equations constant n p = V or 21 12 n p p ⎛⎞ = ⎜⎟ ⎝⎠ V V constant n pv = or n pv = Process work: 22 11 12 1 pp W n VV Process work: 12 1 p vp v Wm n Constants Units Standard atmosphere: 1 atm = 101.3 kPa Standard gravity: g = 9.807 m/s 2 Temperature relation: T (K) = T (ºC) + 273.15 K Universal gas constant: R = 8.314 kJ/(kmol·K) Gas constant, air: R = 0.287 kJ/(kg·K) Molecular weight, air: M = 28.97 kg/kmol Stefan-Boltzmann constant: 82 5.67 10 W/(m K ) σ 4 1 bar = 100 kPa W = J/s J = N·m N = kg·m/s 2 Pa = N/m 2 Energy Transfer in a Steady Internally Reversible Flow with one inlet and one outlet Work: ( ) / out out in in W m w vdp V gz V gz + + + ± ± Heat: / out in Qm q T d s ± ±
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ME 3322 Thermodynamics – Formula Sheet Page 2 Pure Simple Substance Property Models Incompressible Compressible Equation of state: y = tsc ( y 1 , y 2 ) The y -variables represent independent, intrinsic thermodynamic properties.
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This note was uploaded on 09/28/2010 for the course ME 3322 taught by Professor Neitzel during the Fall '07 term at Georgia Institute of Technology.

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Eval- - ME 3322 Thermodynamics Fall 2009 Evaluation Problems Name Date Instructions This is a closed-book closed-notes exam Any necessary equations

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