Chapter 9 - Chapter 9 9.1a. 1/6 b. 1/6 9.2 a P( X = 1)...

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Chapter 9 9.1a. 1/6 b. 1/6 9.2 a ) 1 X ( P = =P(1,1)= 1/36 b ) 6 X ( P = = P(6,6) = 1/36 9.3a P( X = 1) = (1/6) 5 = .0001286 b P( X = 6) = (1/6) 5 = .0001286 9.4 The variance of X is smaller than the variance of X. 9.5 The sampling distribution of the mean is normal with a mean of 40 and a standard deviation of 12/ 100 = 1.2. 9.6 No, because the sample mean is approximately normally distributed. 9.7 a ) 1050 X ( P = - σ μ - 16 / 200 1000 1050 n / X P = P(Z > 1.00) = 1 – P(Z < 1.00) = 1 – .8413 = .1587 b = < ) 960 X ( P - < σ μ - 16 / 200 1000 960 n / X P = P(Z < –.80) = .2119 c = ) 1100 X ( P - σ μ - 16 / 200 1000 1100 n / X P = P(Z > 2.00) = 1 – P(Z < 2.00) = 1 – .9772 = .0228 9.8 a ) 1050 X ( P = - σ μ - 25 / 200 1000 1050 n / X P = P(Z > 1.25) = 1 – P(Z < 1.25) = 1 – .8944 = .1056 b = < ) 960 X ( P - < σ μ - 25 / 200 1000 960 n / X P = P(Z < –1.00) = .1587 c = ) 1100 X ( P - σ μ - 25 / 200 1000 1100 n / X P = P(Z > 2.50) = 1 – P(Z < 2.50) = 1 – .9938 = .0062 9.9 a ) 1050 X ( P = - σ μ - 100 / 200 1000 1050 n / X P = P(Z > 2.50) = 1 – P(Z < 2.50) = 1 – .9938 = .0062 213
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b = < ) 960 X ( P - < σ μ - 100 / 200 1000 960 n / X P = P(Z < –2.00) = .0228 c = ) 1100 X ( P - σ μ - 100 / 200 1000 1100 n / X P = P(Z > 5.00) = 0 9.10 a = < < ) 52 X 49 ( P - < σ μ - < - 4 / 5 50 52 n / X 4 / 5 50 49 P = P(–.40 < Z < .80) = P(Z < .80) − P(Z < −.40) = .7881 −.3446 = .4435 b = < < ) 52 X 49 ( P - < σ μ - < - 16 / 5 50 52 n / X 16 / 5 50 49 P = P(–.80 < Z < 1.60) = P(Z < 1.60) − P(Z < −.80) = .9452 −.2119 = .7333 c = < < ) 52 X 49 ( P - < σ μ - < - 25 / 5 50 52 n / X 25 / 5 50 49 P = P(–1.00 < Z < 2.00) = P(Z < 2.00) − P(Z < −1.00) = .9772 −.1587 = .8185 9.11 a = < < ) 52 X 49 ( P - < σ μ - < - 4 / 10 50 52 n / X 4 / 10 50 49 P = P(–.20 < Z < .40) = P(Z < .40) − P(Z < −.20) = .6554 −.4207= .2347 b = < < ) 52 X 49 ( P - < σ μ - < - 16 / 10 50 52 n / X 16 / 10 50 49 P = P(–.40 < Z < .80) = P(Z < .80) − P(Z < −.40) = .7881 −.3446= .4435 c = < < ) 52 X 49 ( P - < σ μ - < - 25 / 10 50 52 n / X 25 / 10 50 49 P = P(–.50 < Z < 1.00) = P(Z < 1.00) − P(Z < −.50) = .8413 −.3085= .5328 9.12 a = < < ) 52 X 49 ( P - < σ μ - < - 4 / 20 50 52 / 4 / 20 50 49 n X
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Chapter 9 - Chapter 9 9.1a. 1/6 b. 1/6 9.2 a P( X = 1)...

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