Three locations are marked a b are far away from the

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ugh. Three locations are marked, A, B are far away from the loop, so its contribution can be ignored. Location C is at the centre of the loop. Use the formulae provided to calculate the magnetic fields at A, B, C in the paper plane. A current of 1.5 A flows through the wire. Be careful with location C , there are two contributions. The fields are to be specified by magnitude and direction or by listing the appropriate component with sign! 3 4) [5] The particle in the figure has a negative charge, and its velocity vector lies in the x − y plane and makes an angle of 75◦ with the y axis. A magnetic field is along the +x direction. What is the direction of the magnetic force on the particle? Now you are told that the field has a strength of 1.5 T, and that the particle speed is v = 500 m/s. Calculate the magnetic force. 4 FORMULA SHEET ￿ v (tf ) = v (ti ) + ti a(t) dt s(tf ) = s(ti ) + ttif v (t) dt vf = vi + a∆t sf = si + vi ∆t + 1 a∆t2 vf2 = vi2 + 2a∆s 2 ￿ tf g = 9.8 m/s2 f (t) = t f (t) = a = 0 F (t) = f (t) dt = at + C F (t) = anti-derivative = indefinite integral area under the curve f (t) between limits t1 and t2 : F (t2 ) − F (t1 ) x2 + px + q = 0 fac...
View Full Document

This note was uploaded on 09/28/2010 for the course MATH 1025 taught by Professor Tammie during the Fall '10 term at York University.

Ask a homework question - tutors are online