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Unformatted text preview: Physics 62 Quiz 2A Fall 2010 Quiz 2A NAME: §QKW2>¢Q 3 V, SECTION: V surf ace Esra; = 4/80 surface area: 41tR2 (sphere) volume: 415R3/3 (sphere) 21rRh (cylinder) 1cth (cylinder) Circle the best answer (1 point): 1. A point charge +Q is placed at the center of an uncharged, conducting spherical
shell with inner radius 17 and outer radius 217, as shown. The charge on the outer
surface of the conducting shell is: a. 0
+Q ’
C —Q d. +2Q 4Q Circle the best answer (2 points): 2. Consider a closed Gaussian surface in the shape of a hemisphere that contains a Q charge Q. The electric ﬂux through the ﬂat part of the surface is known to be ——. 380
Then the electric ﬂux through the curved surface is Q
1" J1 +5 : Q:
é’D c +9.
380
d_ i9.
380 e
380 Physics 62 Quiz 28 Fall 2010 Quiz ZB NAME: y, SECTION: smf ace 3511512: 4%) ‘ surface area: 47ml?2 (sphere) volume: 41tR3/3 (sphere) ZnRh (cylinder) 1tth (cylinder) Circle the best answer (1 point): 1. 52. A point charge +Q is placed at the center of an uncharged, conducting spherical
shell with inner radius 17 and outer radius 211, as shown. The charge on the inner
surface of the conducting shell is: a. O b. +Q ) d. +2Q +Q 1 Circle the best answer (2 points): Consider a closed Gaussian surface in the shape of a hemisphere that contains a Q charge Q. The electric ﬂux through the flat part of the surface is known to be ——. 380
Then the electric ﬂux through the curved surface is a O b ___Q_
380 C. _4_Q
.380 d + g
380 4
Q +—Q Physics 62 Quiz 23 F all 2010 (7 points) Show all work! 3. A long cylinder of radius R has nonuniform ‘yolume charge density that
varies with distance from the cylinder axis: p(r) : p0 (r/R) , with p0 > 0. A cross
ﬂ, sectional View of the cylinder is shown in the figure. P09 a. Use arrows to indicate the directions of the \
electric field at points P1 and P2 on the figure. < b. Use Gauss's Law to find an expression for the electric field magnitude at all
points inside the cylinder  points such that r < R. Your result should be expressed in terms of po, r, R, and £0. (1+1
x a+1 354% s: #44
éa h
L. 5527/}: :éyfaygﬁgsqudg :QWGL “L _,,272Lt‘3
.4.“ ﬁfjaj_,_vﬂa
6‘9 R 0‘ (Hint: Jxadx = + const., provided 05 #5 l. ) '2. : =~§ E; EOY‘
~ [email protected] c. Find an expression (in terms of po, r, R, and £0) for the electric ﬁeld outside
the cylinder, i.e., all points such that r > R. R
E ‘WhL: :Lﬁ%'%y¢w
3
2 R
:W 2M4 ...
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 Spring '10
 Kruse
 4%, 1 354%, 5 l, 47ml

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