Calculus 2-A3

Calculus 2-A3 - Calculus II Calculus Early Transcendental...

This preview shows pages 1–3. Sign up to view the full content.

Calculus II Calculus: Early Transcendental Functions , 4th ed., by Ron Larson, Robert Hostetler, and Bruce H. Edwards (Boston: Houghton Mifflin, 2007; ISBN-10: 0-618-60624-6). Written Assignment 3 Complete the following textbook exercises for sections 8.7 and 8.8, and submit them to your mentor for correction and grading. Show all calculations. SECTION 8.7 Exercises Do exercises 6, 8, 10, 14, 22, 32, 38, 42, 44, 52, and 54 on page 574 of the textbook. #6 In Exercises 5– 10, evaluate the limit ( a) using techniques from Chapters 2 and 4 and ( b) using L’Hôpital’s Rule. (a) lim (2x-3)(x+1) x->-1 x + 1 = lim (2x-3) x->-1 = -5 (b) L’Hôpital’s Rule lim (d/dx)(2x 2 - x -3)(x+1) x->-1 (d/dx) (x + 1) = lim (4x - 1) x->-1 1 = -5 #8 (a) Using trigonometric limits. .. =2[lim x =>0 [sin(x)/(x)] =2(1) =2 (b) L’Hôpital’s Rule = lim x =>0 [sin(4*0)/(2*0)] = lim x =>0 [sin(0)/(0)] = lim x =>0 [(0)/(0)] = lim x =>0 [4cos(4x)/(2)] = lim x =>0 [2cos(4x)]

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
= lim x =>0 [2cos(4*0)] = 2cos(0) =2 #10 (a) Using trigonometric limits. .. = lim x =>∞ [2x/(4x 2 +x)] + lim x =>∞ [1/(4x 2 +x)] = lim x =>∞ [2/(4x 2 +1)] + lim x =>∞ [1/(4x 2 +x)] = 0/4 = 0 (b) L’Hôpital’s Rule = lim x =>∞ (2x + 1) lim x =>∞ (4x 2 +x) = ∞ indeterminate = lim x =>∞ (2x + 1) (4x 2 +x) = lim x =>∞
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 9

Calculus 2-A3 - Calculus II Calculus Early Transcendental...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online