MAT 232-Calc-1-A5

# MAT 232-Calc-1-A5 - Calculus I Calculus Early...

This preview shows pages 1–4. Sign up to view the full content.

Calculus I Calculus: Early Transcendental Functions , 4th ed., by Ron Larson, Robert Hostetler, and Bruce H. Edwards (Boston: Houghton Mifflin, 2007; ISBN-10: 0-618-60624-6). Written Assignment 5 The written assignment draws on even-numbered exercises from the textbook. Answer all assigned exercises, and show all work. Section Exercises 5.1 6, 10, 12, 32, 38, 54, 56, 70, 74, 80 5.2 2, 10, 16 5.3 6, 28, 44 5.4 10, 14, 18, 28, 32, 38, 40 5.5 14, 30, 52, 56, 62, 88, 92, 102, 106, 110 5.7 6, 8, 20, 30, 54 Section 5.1 6 Find Differential equation & check by differentiation dr / dø = π r = πø + c check: r = πø + c (d / dø) (r) = (d / dø) (πø +c) dr / dø = π 10 Rewrite integrate and simplify ƒ(1 / x 2 )dx rewrite: ƒx -2 dx Integrate: x -1 / -1 +c Simplify: -(1/x) +c 12. ƒx(x 2 +3) dx (multiply it out) rewrite: ƒ(x 3 +3x) dx Integrate: (x 4 / 4) +(3x 2 / 2) + c Simplify: (x 2 / 4) +(x 2 + 6) + c

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
32 Find the Indefinite Integral & check by differentiation ƒ(t 2 – sin t) dt rewrite: (t 2 – cos t) dt Integrate: (t 3 /3)– cos t +c Check: (t 3 /3)– cos t +c = t 2 – sin t 38 ƒsec y (tan y – sec y) dy rewite: (sec y tan y – sec 2 y) dy Integrate: sec y – tan y +c check: d /dy = sec y – tan y +c = sec y tan y – sec 2 y = sec y (tan y – sec y) 54 dy / dx = 2(x – 1) y’=2(x – 1) calculate out y = ƒ (2x – 2) dx y = (2(x 2 /2) – 2x) dx y = x 2 – 2x +c Points: 3,2 2 = 3 2 – 2(3) +c 2 = 9 – 6 + c 2 = 3 + c 2 – 3 = c -1 = c c = -1 y = x 2 – 2x - 1 56 dy / dx = 3 / x y’= 3 - x y = ƒ (3 - x) dx y = (3x - x 2 /2) +c y = 3 - x + c Points: e, 3 3 = 3(e) – e +c 3 = 3e – e + c 3 = 2e + c 3/2 – e = c c = 3/2 – e y = 3 - x + 3/2 70 Solve differential equation ƒ”(x) = sin x, f’(0) = 1, ƒ(0) = 6
ƒ’(x) = -cos x +c 1 ƒ’(0) = 1 ƒ’(0) = -1 + c 1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern