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Unformatted text preview: cone pine that is 3000 y old? 14 C 14 N + et 1/2 = 5730 y ln{N o /N} = kt ln x = y y = e x ln 2 = kt 1/2 What percent of the original 14 C remains in the heartwood of a bristle cone pine that is 3000 y old? 14 C 14 N + et 1/2 = 5730 y ln{N o /N} = kt ln x = y y = e x 69.6 % ln 2 = kt 1/2 Question #3 N.B.E. usually in energy per atom in eV or MeV 14 7 N 7 1 1 H + 7 1 n 14.0031 amu 14.11543 amu N.B.E. = 1.68 x 1011 J/nuclide 1 MeV/nuclide = 1.60 x 1013 J/nuclide N.B.E. = 105 MeV Nuclear Binding Energy BE / nucleon = BE / nucleon = BE nucleon = Nuclear binding energy Mass number 1.009 x 10 10 kJ/mole N14 14 mole p & n = 7.221 x 10 8 kJ/mole of nucleons 105 MeV/N14 nucleus 14 nucleons/N14 nucleus = 7.50 MeV / nucleon NBE: Clue to the type of nuclear reactions...
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 Spring '09
 GABORACSATHY

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