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161E1-S2005 - MA 161& 161E EXAM 1 SPRING 2005 Page 2 of...

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Unformatted text preview: MA 161 & 161E EXAM 1 SPRING 2005 Page 2 of 5 1 1. 2332—2a:+1 1 . $530 3_ 43:2 equas 2a:+1 ifa:>1, x—6 ifa:<1. 2. Let m) ={ What value should f (1) be given to make f continuous from the right at a: = 1 ? (A) 1 B —5 00 ) ) ) U —1 E) 0 AAAA O MA 161 & 161E EXAM 1 SPRING 2005 Page 3 0f 5 3. If f(:I:) = 3:173 —1 then f_1(—25) equals A) Obj MOI—I ) ) ) U ( ( ( (—1 (_ E)2 2 __2 _ 4. Set f (:12) = f——x_x—48 . Then 91:13}! f(:I:) equals A) 00:: U prbouoo ( () () () (E) () ( (B)fog(2)= and g°f(2)=—2 (C)fog(2)=—4 and gof(2)=4 (D)fog(2)=-2 and 90f(2)=2 (E)fog(2)=4 and g°f(2)=4 MA 161 & 161E EXAM 1 SPRING 2005 Page 4 of 5 6. The range of f (2:) = sin2 :1: is MA 161 & 161E EXAM 1 SPRING 2005 Page 5 of 5 8. Find the domain for f(:v) = $2 — 33: + 2 . (C) 18 $2- a: (D) ,—————$2 _1 (E) v1— :32 (L' 9(03) f(a:) + 2 10. If f and g are continuous with f (2) = 4 and lim ( m—)2 ) = 3 then 9(2) equals 8 E AAAA HUGE} VVVV [000»th ...
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